Systems Word Problems
Two unknowns, two facts, and a reliable setup routine.
The explanation
If a problem has two unknowns, you need two separate facts about them.
The routine:
1. Define both variables in writing, with units.
2. Write one equation per fact given.
3. Solve by substitution or elimination.
4. Answer the actual question in a sentence.
Common patterns:
- Totals: a count equation plus a value equation. 12 coins worth $2.10 gives n + d = 12 and 0.05n + 0.10d = 2.10.
- Mixtures: a total amount plus a total concentration.
- Rates: distance = rate × time for each traveller.
Money problems are the classic trap. Counting coins and valuing coins are two different equations, and mixing them up produces nonsense.
Modelling with a system requires two independent relationships. Two restatements of the same fact produce a dependent system with no unique solution, which is a modelling error rather than an algebraic one.
The standard families each have a canonical structure. Count-and-value problems pair x + y = total count with ax + by = total value. Mixture problems pair volumes with c₁V₁ + c₂V₂ = c_f V_f for concentrations. Uniform-motion problems build each row from d = rt, with the relationship between the two rows (equal distances, or distances summing to a total) supplying the second equation.
Units are the strongest check available: every term in an equation must share units, so an equation adding coins to dollars is malformed by inspection.
Finally, the algebraic solution must be tested against the context. A negative count or a fractional person indicates a setup error even when the arithmetic is flawless.
Worked example
Tickets cost $8 for adults and $5 for children. 200 tickets sold for $1,330. How many of each?
- Let a = adult tickets, c = child tickets.
- Count: a + c = 200. Value: 8a + 5c = 1330.
- From the first, c = 200 − a. Substitute: 8a + 5(200 − a) = 1330.
- 8a + 1000 − 5a = 1330 → 3a = 330 → a = 110, so c = 90.
Answer: 110 adult and 90 child tickets
Common mistakes
- Writing only the count equation and trying to solve one equation with two unknowns.
- Using cents in one equation and dollars in the other.