Algebra 2 Core complex numbersimaginaryi

Imaginary & Complex Numbers

Inventing i so that √(−1) has an answer.

Video by Khan Academy — “Introduction to i and imaginary numbers | Imaginary and complex numbers | Precalculus | Khan Academy” Watch on YouTube

The explanation

Key idea i = √(−1), so i² = −1.

No real number squares to a negative, so mathematicians defined a new one: i, with i² = −1.

That makes √(−25) = 5i, since (5i)² = 25i² = −25.

A complex number combines a real and an imaginary part: a + bi. In 3 − 4i, the real part is 3 and the imaginary part is −4.

Powers of i cycle every four: i¹ = i, i² = −1, i³ = −i, i⁴ = 1, then it repeats. To find a high power, divide the exponent by 4 and use the remainder.

Add and subtract by combining like parts. Multiply with FOIL, then replace i² with −1.

Worked example

Simplify (3 + 2i)(4 − 5i) and find i²³.

  1. FOIL: 12 − 15i + 8i − 10i².
  2. Replace i² with −1: 12 − 7i + 10.
  3. Combine: 22 − 7i.
  4. 23 ÷ 4 leaves remainder 3, so i²³ = i³ = −i.

Answer: 22 − 7i, and i²³ = −i

Common mistakes

  • Leaving i² in an answer instead of replacing it with −1.
  • Multiplying √(−4)·√(−9) as √36.