Algebra 1 Core sequencesgeometriccommon ratio

Geometric Sequences

Multiplying by the same amount each time — an exponential on the integers.

Video by Khan Academy — “Introduction to geometric sequences | Sequences, series and induction | Precalculus | Khan Academy” Watch on YouTube

The explanation

Key idea aₙ = a₁·r^(n−1).

A geometric sequence multiplies by a fixed amount, the common ratio r, each step.

3, 6, 12, 24, … has r = 2.
81, 27, 9, 3, … has r = 1/3.

Any term is given by:
aₙ = a₁·r^(n−1)

The 8th term of 3, 6, 12, …: a₈ = 3·2⁷ = 384.

Find r by dividing any term by the one before it. Division, not subtraction — that is the whole distinction from arithmetic.

A negative ratio makes the signs alternate: 2, −6, 18, −54 has r = −3.

Worked example

For 5, 20, 80, …, find the 7th term. Then find the sum of the infinite series 8 + 4 + 2 + 1 + …

  1. r = 20/5 = 4, a₁ = 5.
  2. a₇ = 5·4⁶ = 5(4096) = 20,480.
  3. Second series: a₁ = 8, r = 1/2, and |r| < 1 so it converges.
  4. S = 8/(1 − 1/2) = 8/(1/2).

Answer: a₇ = 20,480; the infinite sum is 16.

Common mistakes

  • Finding r by subtracting consecutive terms.
  • Applying the infinite sum formula when |r| ≥ 1, where the series has no finite sum.