Arithmetic Sequences
Adding the same amount each time — a linear function on the integers.
The explanation
An arithmetic sequence adds a fixed amount, the common difference d, each step.
4, 7, 10, 13, … has d = 3.
To find any term without listing them all:
aₙ = a₁ + (n − 1)d
The 20th term of that sequence: a₂₀ = 4 + 19(3) = 61.
The (n − 1) trips people up. The first term needs zero jumps, the second needs one, so the nth needs n − 1.
Find d by subtracting any term from the one after it. If those differences are not all equal, it is not arithmetic.
An arithmetic sequence satisfies the recursive definition aₙ = aₙ₋₁ + d with a₁ given, and the explicit formula aₙ = a₁ + (n − 1)d.
The explicit form is a linear function restricted to the positive integers: rewriting it as aₙ = dn + (a₁ − d) shows slope d and intercept a₁ − d. That is why plotted terms are collinear and why arithmetic sequences and linear functions share their structure — the difference is a discrete domain rather than a continuous one.
The sum of the first n terms is Sₙ = n(a₁ + aₙ)/2, the count times the average of the first and last terms. Gauss's pairing argument gives it directly: adding the sequence to its own reversal pairs every position into the same total a₁ + aₙ, and there are n such pairs counted twice.
Both formulas can be solved for any variable, so problems asking "which term equals 61" are handled by substituting and solving for n — with a non-integer result meaning the value never appears.
Worked example
For 7, 11, 15, 19, …, find the 30th term and the sum of the first 30 terms.
- d = 11 − 7 = 4, a₁ = 7.
- a₃₀ = 7 + 29(4) = 7 + 116 = 123.
- S₃₀ = 30(7 + 123)/2 = 30(130)/2.
Answer: a₃₀ = 123 and S₃₀ = 1,950
Common mistakes
- Using n instead of n − 1 in the formula.
- Assuming a sequence is arithmetic without checking every consecutive difference.