Remainder & Factor Theorems
Testing whether something is a factor without dividing all the way.
The explanation
The Remainder Theorem: dividing P(x) by (x − c) leaves a remainder of exactly P(c).
So to find a remainder, you can just substitute. No division required.
The Factor Theorem is the special case where that remainder is zero: if P(c) = 0, then (x − c) is a factor, and c is a root.
These three statements describe the same fact:
- c is a root of P
- (x − c) is a factor of P
- (c, 0) is an x-intercept of the graph
That equivalence is the reason factoring finds roots, and finding roots helps you factor.
From the division algorithm P(x) = (x − c)Q(x) + R with R constant, substituting x = c gives P(c) = R — the Remainder Theorem. The Factor Theorem is the case R = 0.
The practical procedure for a higher-degree polynomial is: find one root (by inspection, the rational root theorem, or a graph), divide it out synthetically to depress the degree, and repeat on the quotient until it is quadratic and can be solved directly.
The equivalence of root, factor and x-intercept underlies the connection between algebra and graphing throughout the course. It also extends to multiplicity: (x − c)^m divides P exactly when c is a root of multiplicity m.
Note that the theorems hold over any field, including ℂ, so a complex root c yields a complex linear factor. Combined with the Fundamental Theorem of Algebra, this gives the complete factorisation of any polynomial into linear factors over ℂ.
Worked example
Is (x − 2) a factor of P(x) = x³ − 3x² + 4x − 4? What is the remainder on dividing by (x + 1)?
- P(2) = 8 − 12 + 8 − 4 = 0, so yes.
- For (x + 1), c = −1.
- P(−1) = −1 − 3 − 4 − 4 = −12.
Answer: (x − 2) is a factor; dividing by (x + 1) leaves remainder −12.
Common mistakes
- Substituting x = −2 to test the factor (x − 2).
- Concluding a nonzero remainder means the polynomial cannot be factored at all.