The Converse & Pythagorean Triples
Using a² + b² = c² backwards to classify any triangle.
The explanation
The Pythagorean theorem tells you a side when you already know the triangle is right. Its converse runs the other way: if a² + b² = c², the triangle *must* be right.
That turns it into a classification test. With c as the longest side:
- a² + b² = c² → right
- a² + b² > c² → acute
- a² + b² < c² → obtuse
For 6, 8, 11: 36 + 64 = 100, which is less than 121, so the triangle is obtuse.
Pythagorean triples are whole-number side sets. Knowing them on sight saves real time: 3-4-5, 5-12-13, 8-15-17, 7-24-25, 9-40-41.
Any multiple of a triple is also a triple, so 6-8-10 and 30-40-50 are both right triangles.
The converse states that if a² + b² = c² with c the longest side, the angle opposite c is right. It is proved by constructing a right triangle with legs a and b, applying the theorem to get hypotenuse c, and concluding congruence by SSS.
The comparison version generalises this into a classification and follows from the Law of Cosines, c² = a² + b² − 2ab·cos C: the sign of a² + b² − c² matches the sign of cos C, which is positive for acute C, zero for right and negative for obtuse.
A necessary first check is the triangle inequality — 3, 4, 20 satisfies no triangle at all, so classifying it is meaningless.
Primitive Pythagorean triples are those with gcd(a,b,c) = 1, and all are generated by a = m² − n², b = 2mn, c = m² + n² for coprime m > n of opposite parity. Scaling any triple by an integer produces another, which is why recognising 9-12-15 as 3×(3,4,5) is faster than computing.
Worked example
Classify the triangles with sides (9, 12, 15) and (7, 9, 12).
- First: 81 + 144 = 225 and 15² = 225.
- Equal, so right — it is 3×(3,4,5).
- Second: 49 + 81 = 130 and 12² = 144.
- 130 < 144.
Answer: (9,12,15) is right; (7,9,12) is obtuse.
Common mistakes
- Comparing against a side that is not the longest.
- Reversing the inequality, calling a² + b² > c² obtuse.