Graphing Parabolas
Vertex, axis of symmetry, direction, and how wide it opens.
The explanation
The graph of a quadratic is a parabola, a U-shape.
- If a > 0 it opens up and the vertex is the minimum.
- If a < 0 it opens down and the vertex is the maximum.
- Larger |a| makes it narrower.
Find the vertex first. Its x-coordinate is −b/(2a); substitute back to get the y-coordinate.
The axis of symmetry is the vertical line through the vertex, x = −b/(2a). The parabola mirrors across it, so once you plot points on one side you get the other side free.
The y-intercept is c, available with no work at all.
A quadratic function f(x) = ax² + bx + c with a ≠ 0 graphs as a parabola with axis of symmetry x = −b/(2a) and vertex (−b/(2a), f(−b/(2a))). The axis formula follows from completing the square, which rewrites the function in vertex form a(x − h)² + k with h = −b/(2a).
The parameter a controls both direction and vertical stretch; it is the same a as in the transformation a·f(x) applied to the parent function y = x².
The range follows from the vertex: [k, ∞) for a > 0 and (−∞, k] for a < 0. The domain is always ℝ.
Zeros, if real, are symmetric about the axis, so their average is exactly −b/(2a) — which provides both a fast route to the vertex once you have the roots and a check on the roots once you have the vertex. The number of real zeros is governed by the discriminant b² − 4ac.
Worked example
Graph y = x² − 6x + 5: find the vertex, axis, intercepts and range.
- Axis: x = −(−6)/(2·1) = 3.
- Vertex y: 9 − 18 + 5 = −4, so vertex (3, −4).
- y-intercept: c = 5, at (0, 5).
- Zeros: x² − 6x + 5 = (x − 1)(x − 5), so x = 1 and 5.
Answer: Vertex (3, −4), axis x = 3, intercepts (0,5), (1,0), (5,0), range [−4, ∞), opens up.
Common mistakes
- Forgetting the negative in −b/(2a).
- Reporting only the x-coordinate as the vertex.