Algebra 1 Core parabolavertexgraphing

Graphing Parabolas

Vertex, axis of symmetry, direction, and how wide it opens.

Video by The Organic Chemistry Tutor — “Graphing Quadratic Functions In Vertex Form” Watch on YouTube

The explanation

Key idea For y = ax² + bx + c, the vertex is at x = −b/(2a).

The graph of a quadratic is a parabola, a U-shape.

  • If a > 0 it opens up and the vertex is the minimum.
  • If a < 0 it opens down and the vertex is the maximum.
  • Larger |a| makes it narrower.

Find the vertex first. Its x-coordinate is −b/(2a); substitute back to get the y-coordinate.

The axis of symmetry is the vertical line through the vertex, x = −b/(2a). The parabola mirrors across it, so once you plot points on one side you get the other side free.

The y-intercept is c, available with no work at all.

Worked example

Graph y = x² − 6x + 5: find the vertex, axis, intercepts and range.

  1. Axis: x = −(−6)/(2·1) = 3.
  2. Vertex y: 9 − 18 + 5 = −4, so vertex (3, −4).
  3. y-intercept: c = 5, at (0, 5).
  4. Zeros: x² − 6x + 5 = (x − 1)(x − 5), so x = 1 and 5.

Answer: Vertex (3, −4), axis x = 3, intercepts (0,5), (1,0), (5,0), range [−4, ∞), opens up.

Common mistakes

  • Forgetting the negative in −b/(2a).
  • Reporting only the x-coordinate as the vertex.