Algebra 2 Advanced enatural logcontinuous growth

e and Natural Logarithms

The number that shows up whenever growth is continuous.

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The explanation

Key idea e ≈ 2.71828, and ln is log base e.

e is a specific number, about 2.71828, like π is about 3.14159.

It appears whenever growth is continuous rather than in steps. If interest compounds every instant instead of monthly, the formula becomes A = Pe^(rt).

ln means log base e. It is the inverse of eˣ, so:
ln(eˣ) = x and e^(ln x) = x.

Where does e come from? Compound $1 at 100% for a year. Yearly gives $2. Monthly gives $2.61. Daily gives $2.7146. Every instant gives e.

All the log properties apply to ln unchanged. It is a logarithm like any other, with a base that happens to be irrational.

Worked example

$2,000 is invested at 4.5% compounded continuously. Find the value after 7 years, and the time to double.

  1. A = 2000e^(0.045×7) = 2000e^0.315.
  2. e^0.315 ≈ 1.3702, so A ≈ $2,740.42.
  3. Doubling: 2 = e^(0.045t), so ln 2 = 0.045t.
  4. t = 0.6931/0.045.

Answer: About $2,740.42; doubling takes about 15.4 years.

Common mistakes

  • Treating e as a variable rather than a constant.
  • Using the annual formula A = P(1 + r)^t when the problem says continuously.