Circles & Parabolas as Conics
Centre-radius form, and completing the square to find it.
The explanation
A circle with centre (h, k) and radius r has equation:
(x − h)² + (y − k)² = r²
For (x − 2)² + (y + 3)² = 25: centre (2, −3), radius 5. Watch the signs — y + 3 means k = −3 — and remember the right side is r², so the radius is √25 = 5.
If the equation is expanded instead, complete the square on both x and y to recover this form.
Parabolas are the other conic you meet in Algebra 2. y = a(x − h)² + k opens vertically; x = a(y − k)² + h opens horizontally. Swapping which variable is squared is what turns the parabola on its side.
Conic sections arise as intersections of a plane with a double cone, producing circles, ellipses, parabolas and hyperbolas. Their general second-degree equation is Ax² + Bxy + Cy² + Dx + Ey + F = 0, and with B = 0 the type is determined by A and C: equal gives a circle, same sign and unequal gives an ellipse, opposite signs gives a hyperbola, and exactly one of them zero gives a parabola.
The centre-radius form follows from the distance formula: (x − h)² + (y − k)² = r² states that every point is r from the centre, so it is the Pythagorean theorem written as a locus.
Converting from expanded form requires completing the square in both variables, the same procedure as for quadratics but applied twice. A negative result on the right indicates no real graph, and zero indicates the degenerate case of a single point.
Each conic also has a focus-directrix definition: a parabola is the locus equidistant from a focus and a directrix, which is why parabolic reflectors focus parallel rays to a point.
Worked example
Find the centre and radius of x² + y² − 6x + 4y − 12 = 0.
- Group: (x² − 6x) + (y² + 4y) = 12.
- Complete both squares: add 9 and 4 to both sides.
- (x − 3)² + (y + 2)² = 12 + 9 + 4 = 25.
Answer: Centre (3, −2), radius 5
Common mistakes
- Reporting r² as the radius.
- Adding the completing constants to the left side only.